12+58\dfrac{1}{2} + \dfrac{5}{8}
12+58\dfrac{1}{2} + \dfrac{5}{8}
Since these fractions have different denominators, we need to find the least common multiple of the denominators
The least common multiple of 2 and 8 is 8, so we need to multiply to make each of the denominators = 8
12∗44=48\dfrac{1}{2} * \dfrac{4}{4} = \dfrac{4}{8}
58∗11=58\dfrac{5}{8} * \dfrac{1}{1} = \dfrac{5}{8}
Since these fractions have the same denominator, we can just add the numerators
48+58=98\dfrac{4}{8} + \dfrac{5}{8} = \dfrac{9}{8}
Because 98\dfrac{9}{8} is an improper fraction (the numerator is greater than the denominator), we need to convert it to a mixed number
98=118\dfrac{9}{8} = 1\dfrac{1}{8}