12+56\dfrac{1}{2} + \dfrac{5}{6}
12+56\dfrac{1}{2} + \dfrac{5}{6}
Since these fractions have different denominators, we need to find the least common multiple of the denominators
The least common multiple of 2 and 6 is 6, so we need to multiply to make each of the denominators = 6
12∗33=36\dfrac{1}{2} * \dfrac{3}{3} = \dfrac{3}{6}
56∗11=56\dfrac{5}{6} * \dfrac{1}{1} = \dfrac{5}{6}
Since these fractions have the same denominator, we can just add the numerators
36+56=86\dfrac{3}{6} + \dfrac{5}{6} = \dfrac{8}{6}
86\dfrac{8}{6} can be reduced, since 22 is a factor of both 88 and 66:
86÷22=43\dfrac{8}{6} \div \dfrac{2}{2} = \dfrac{4}{3}
The fraction is now in lowest terms
Because 43\dfrac{4}{3} is an improper fraction (the numerator is greater than the denominator), we need to convert it to a mixed number
43=113\dfrac{4}{3} = 1\dfrac{1}{3}