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1
2
+
1
2
\dfrac{1}{2} + \dfrac{1}{2}
2
1
+
2
1
1
2
+
1
2
\dfrac{1}{2} + \dfrac{1}{2}
2
1
+
2
1
Since these fractions have the same denominator, we can just add the numerators
1
2
+
1
2
=
2
2
\dfrac{1}{2} + \dfrac{1}{2} = \dfrac{2}{2}
2
1
+
2
1
=
2
2
2
2
\dfrac{2}{2}
2
2
can be reduced, since
2
2
2
is a factor of both
2
2
2
and
2
2
2
:
2
2
÷
2
2
=
1
\dfrac{2}{2} \div \dfrac{2}{2} = 1
2
2
÷
2
2
=
1
The fraction is now in lowest terms