12+16\dfrac{1}{2} + \dfrac{1}{6}
12+16\dfrac{1}{2} + \dfrac{1}{6}
Since these fractions have different denominators, we need to find the least common multiple of the denominators
The least common multiple of 2 and 6 is 6, so we need to multiply to make each of the denominators = 6
12∗33=36\dfrac{1}{2} * \dfrac{3}{3} = \dfrac{3}{6}
16∗11=16\dfrac{1}{6} * \dfrac{1}{1} = \dfrac{1}{6}
Since these fractions have the same denominator, we can just add the numerators
36+16=46\dfrac{3}{6} + \dfrac{1}{6} = \dfrac{4}{6}
46\dfrac{4}{6} can be reduced, since 22 is a factor of both 44 and 66:
46÷22=23\dfrac{4}{6} \div \dfrac{2}{2} = \dfrac{2}{3}
The fraction is now in lowest terms