13+16\dfrac{1}{3} + \dfrac{1}{6}
13+16\dfrac{1}{3} + \dfrac{1}{6}
Since these fractions have different denominators, we need to find the least common multiple of the denominators
The least common multiple of 3 and 6 is 6, so we need to multiply to make each of the denominators = 6
13∗22=26\dfrac{1}{3} * \dfrac{2}{2} = \dfrac{2}{6}
16∗11=16\dfrac{1}{6} * \dfrac{1}{1} = \dfrac{1}{6}
Since these fractions have the same denominator, we can just add the numerators
26+16=36\dfrac{2}{6} + \dfrac{1}{6} = \dfrac{3}{6}
36\dfrac{3}{6} can be reduced, since 33 is a factor of both 33 and 66:
36÷33=12\dfrac{3}{6} \div \dfrac{3}{3} = \dfrac{1}{2}
The fraction is now in lowest terms