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1
3
+
2
3
\dfrac{1}{3} + \dfrac{2}{3}
3
1
+
3
2
1
3
+
2
3
\dfrac{1}{3} + \dfrac{2}{3}
3
1
+
3
2
Since these fractions have the same denominator, we can just add the numerators
1
3
+
2
3
=
3
3
\dfrac{1}{3} + \dfrac{2}{3} = \dfrac{3}{3}
3
1
+
3
2
=
3
3
3
3
\dfrac{3}{3}
3
3
can be reduced, since
3
3
3
is a factor of both
3
3
3
and
3
3
3
:
3
3
÷
3
3
=
1
\dfrac{3}{3} \div \dfrac{3}{3} = 1
3
3
÷
3
3
=
1
The fraction is now in lowest terms